For more discuss and ask question
join this group
Posted By : Tahir Siddiqui(Mani)
Total Marks
5 | |
Starting Date | Wednesday, July 27, 2016 |
Closing Date | Thursday, July 28, 2016 |
Status | Open |
Question Title | Graded Discussion Board |
Graded Discussion Board Topic
Binary
language or machine language is the basic language of computer system
and it consists of zeros and ones. As it is a universal fact that modern
digital computers understand and store data in the form of binary
language i.e. 0, 1. Where ‘0’ represents OFF/Absent while ‘1’ represents
ON/Present in electronic circuits.
Now assume that you are designing a computer system that is supposed to operate on tertiary language i.e. -1, 0, 1. In your opinion how will it affect the storage of computer systems?Support your answer with valid arguments.
Read the following instructions carefully before sending your comments
- Your discussion must be based on logical facts.
- Your comments should be relevant to the topic i.e. clear and concise (Maximum 4-5 lines answer).
- You should post your comments on Graded Discussion Board & not on the Regular MDB. Both will run parallel to each other during the time specified above.
- Books, websites and other reading material may be consulted before posting your comments. (Do not copy the material as it is.)
- GDB will have weight-age of 5% of your total subject marks.
- No extra time will be given for discussion.
- You cannot participate in the discussion after the due date or through e-mail.
1MB m 1024 bytes hoty hain i think so why u write in this 1MB has 1048566 bytes can u tell me which caluculation is used in this gdb
ReplyDeleteSome researchers are trying to get a memory cell capable of having 3 states instead of 2.
ReplyDelete1) How many memory cells, in principle and as a rough estimate, does a typical 1 megabyte memory chip has? is it 8*1024 cells?
2) If you have N memory cells, each has x logical levels, what is the number of possible representations that we can get out of it? is it x^N representations?
Let's take Binary system as an example. Say we have 8*1024 memory cells. We can store only one of the possible 2^N representations in each cell, so at the end the number of stored bits is just N=8*1024. Now, for Ternary system, the gain is log2(3) ~ 1.58 times so we can store ~ 1.58 * 8 * 1024 "bits" or 8*1024*1024 "trits".